It will start off as blue/black as there is starch in the solution however you will know when there is no more starch as the iodine in the solution will turn a red/brown colour
HANNAH!!! YOU ARE AMAZING!!!THIS BLOG IS THE REASON IM NOT SO STRESSED OUT! PLEASE KEEP GOING, KNOWING THAT YOU HAVE HELPED ME SO MUCH.....THANK YOU THANK YOU THANK YOU!!!!
Is it fine if I wrote Enzyme catalase ,which breaks hydrogen peroxide into water and hydrogen Catalase in found in potatoes , therefore putting potato chips into preoxide will produce O2 .the rate of reaction is therefore proportional to the volume of 02 given off. The changing in temperature will alter the volume
Hannah helped.
ReplyDeleteHaha I'm gald!
Deletethank you so much!
Deletewill the product be a simple sugar?
ReplyDeleteYes, because amylase breaks down starch into the sugar maltose, which is a simple sugar.
DeleteYes that's right, thanks for helping :)
DeleteNo probs
ReplyDeleteWhat colour will the iodine turn when it stops being blue/black??
ReplyDeleteThis comment has been removed by the author.
Deleteorange/red
DeleteDoesnt it have to change to Blue Black, because it is Iodine??? Red to Blue Black, it said in like 2.7 of your blog???
ReplyDeleteDoesnt it have to change to Blue Black, because it is Iodine??? Red to Blue Black, it said in like 2.7 of your blog???
ReplyDeleteIt will start off as blue/black as there is starch in the solution however you will know when there is no more starch as the iodine in the solution will turn a red/brown colour
ReplyDeletehannah helped once again
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ReplyDeleteMust you add the amylase after the glucose is heated?
ReplyDeletethx soo much
ReplyDeleteHANNAH!!! YOU ARE AMAZING!!!THIS BLOG IS THE REASON IM NOT SO STRESSED OUT! PLEASE KEEP GOING, KNOWING THAT YOU HAVE HELPED ME SO MUCH.....THANK YOU THANK YOU THANK YOU!!!!
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Is it fine if I wrote
ReplyDeleteEnzyme catalase ,which breaks hydrogen peroxide into water and hydrogen
Catalase in found in potatoes , therefore putting potato chips into preoxide will produce O2 .the rate of reaction is therefore proportional to the volume of 02 given off. The changing in temperature will alter the volume
How enzyme activity can be affected by changes in temperature
ReplyDeleteCan someone help me please
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ReplyDeletepls explain it briefly
ReplyDeleteHow would you test for the product formed?
ReplyDelete